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Ovo i ono sve što nije našlo mesta u ostalim temama, naćiće mesto ovde...

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Old 28-08-2009   #261
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da nije 54 .........
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Old 28-08-2009   #262
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ja mislim da je tačno
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Old 28-08-2009   #263
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Quote:
Originally Posted by Zijadina View Post
da nije 54 .........


Bravo. Jos objasni.
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Old 28-08-2009   #264
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1,5 = 36h = 1,5
1,0 = 36h = 1,0
_______________
jedna guska snese za 36h sati 1 jaje, u 9 dana (216h) ce sneti 6 jaja.

9 x 6 = 54
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Old 28-08-2009   #265
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......-----
......| X |
----------------
| X | X | X |
----------------
| X | X | X |
----------------
......| X |
...... ----

Zadatak:

umesto znaka "x" trebaju da se poredjaju brojevi od 1 do 8.
susedni brojevi se nesmiju dotachinjati ( njihove polja, tj. ni vertikalno ni horizontalno a ni diagonalno)
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Old 28-08-2009   #266
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E sad da rjesavam Zijadinin zadatak

Last edited by Skorpija; 28-08-2009 at 16:21..
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Old 28-08-2009   #267
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OK je! ZIKI
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Old 28-08-2009   #268
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Quote:
Originally Posted by Skorpija View Post
1,5 = 36h = 1,5 ovo je tačno ZIKI ali posle proizilazi iz ovoga da

1,0 = 36h = 1,0 netačno tačno je 24h za 1 jedno jaje

sledi 24h X 9dana je 216h
ako je potrebno 24 sata za 1 jaje onda sledi
da je 24 h (1 jaje) x 9 dana = 9 jaja ...znachi
24h = 1 jaje
216h = 9 jaja

znachi .....sto bi sledelo da je 9 kokosaka x 9 jaja = 81 i to bi po mom razmisljanju bilo netachno

logichno razmisljajuci ...
npr.

2 choveka pojedu za 36 sati 2 hleba
1 chovek znachi pojede za tih 36 sati 1 hleb

2,0 = 36h = 2,0
1,0 = 36h = 1,0
i zato mislim da je moje objasnjenje bilo tachno
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Old 28-08-2009   #269
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da malo uprostim....

u 9 dana jedan i po dan ide 6 puta,sto zanci da jedna guska snese za 9 dana 6 jaja,pa puta 9 gusaka....

matematichki : (9:1.5)x9=6x9=54
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Old 28-08-2009   #270
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a da ziki...

ako sam skontala....

(
(3)(6)(2)
(7)(1)(4)
(5)

jbg,ubi se dok ne napisah ovo....
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Old 28-08-2009   #271
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Quote:
Originally Posted by Zijadina View Post
......-----
......| 8 |
----------------
| 3 | 6 | 2 |
----------------
| 7 | 1 | 4 |
----------------
......| 5 |
...... ----

Zadatak:

umesto znaka "x" trebaju da se poredjaju brojevi od 1 do 8.
susedni brojevi se nesmiju dotachinjati ( njihove polja, tj. ni vertikalno ni horizontalno a ni diagonalno)
ubi me al ne mogu napisati,jbg....
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Old 28-08-2009   #272
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1 i 2 ti se dodiruju, kao i 6 i 7 a i 4 i 5
nesmiju da se dodiruju, pa chak ni coshkovi (diagonalno)

ps:
i ovde postoji logichno razmislanje, nije na srecu
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Old 28-08-2009   #273
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nisam videla dijagonalno....da ne sme...cek malo...
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Old 28-08-2009   #274
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Quote:
Originally Posted by Zijadina View Post
......-----
......| 7 |
----------------
| 4 | 1 | 3 |
----------------
| 6 | 8 | 5 |
----------------
......| 2 |
...... ----

Zadatak:

umesto znaka "x" trebaju da se poredjaju brojevi od 1 do 8.
susedni brojevi se nesmiju dotachinjati ( njihove polja, tj. ni vertikalno ni horizontalno a ni diagonalno)
najveci i najmanji moraju biti u sredini,jer imaju samo jednog suseda....
valjda sad skontah....nisam dobro procitala...prvi put...
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Old 28-08-2009   #275
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hehhe.....

pa nisam prvi put ni pomenula da treba logichno da se razmislja

chobanice... da vidimo sta cesh nam ti priredit od zadatka ili pitanja







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Old 28-08-2009   #276
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Quote:
Originally Posted by cobanica View Post
da malo uprostim....

u 9 dana jedan i po dan ide 6 puta,sto zanci da jedna guska snese za 9 dana 6 jaja,pa puta 9 gusaka....

matematichki : (9:1.5)x9=6x9=54
E tako brate slatki uprošteno

BRAVO ČOBANICE
ZIJADINA I TEBI BRAVO ali uprosti objašnjenje nama đacima. POZZZ
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Old 28-08-2009   #277
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moze i ovako

1.5 kokosaka......snese 1.5 jaje za 1.5 dana

9 kokosaka .......snese x jaja za .....1.5dana

prvo resimo po x u intervalu od 1.5 dana

=>x=1.5*9/1.5= 9 jaja za za interval od 1.5 dana

a zatim za interval od jednog dana


9 jaja za 1.5 dan=x jaja za 1 dan
=>x= 9/1.5=6 jaja za jedan dan snese 9 kokosaka

znaci 9 kokosaka snese 6 jaja za jedan dan,
a za 9 dana ce sneti 9*6=54 ps.....mogu biti i guske
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Old 28-08-2009   #278
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Quote:
Originally Posted by Skorpija View Post
E tako brate slatki uprošteno

BRAVO ČOBANICE
ZIJADINA I TEBI BRAVO ali uprosti objašnjenje nama đacima. POZZZ
pa moje PRVO obijasjenje je bilo isto tako prosto...ispred onog zaprtljanog
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Old 28-08-2009   #279
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Imate pet trojki 3 3 3 3 3, uz pomoc nekih aritmetickih operacija treba da dobijete broj 31.
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Old 28-08-2009   #280
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(3:3)+(3ł)+3=
1 + 27 + 3=
31
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